4 Event Probability Calculator

This 4 event probability calculator finds the chance that all four independent events happen, none happen, at least one happens, or exactly one, two or three happen. Enter each probability and see the working.

Checks on your data

  • These results assume the events are independent: one happening does not change the chance of another. For dependent events (cards drawn without replacement, linked failures) the true values differ.

Results

All 4 events occur P(A ∩ B ∩ C ∩ D)
0.009
0.9 %
None occur
0.126
12.6 %
At least one occurs P(A ∪ B ∪ …)
0.874
87.4 %
Exactly 1 of 4 occur
0.383
38.3 %
Exactly 2 of 4 occur
0.365
36.5 %
Exactly 3 of 4 occur
0.117
11.7 %
At least 2 occur
0.491
49.1 %
Expected number of events
1.5
Probability of exactly k events occurring
00.10.20.30: 0.12600.1261: 0.38310.3832: 0.36520.3653: 0.11730.1174: 0.00940.009
Single-event probabilities
00.20.40.6A: 0.6A0.6B: 0.5B0.5C: 0.3C0.3D: 0.1D0.1
Probability of exactly k events
k events occurProbabilityAt least k
00.1261
10.3830.874
20.3650.491
30.1170.126
40.0090.009
Show step-by-step solution
  1. Assuming independence, P(all) = 0.6 × 0.5 × 0.3 × 0.1 = 0.009.
  2. P(none) = (1 − 0.6) × (1 − 0.5) × (1 − 0.3) × (1 − 0.1) = 0.126.
  3. P(at least one) = 1 − P(none) = 0.874.
  4. P(exactly k) is found by adding the probabilities of every combination with k events happening and the rest failing: k=0: 0.126, k=1: 0.383, k=2: 0.365, k=3: 0.117, k=4: 0.009.
All fourProduct of the four
At least one1 − Π(1 − pᵢ)
Exactly kSum over combinations
AssumesIndependence

What Is Probability of 4 Events?

For four independent events, the probability that all occur is the product of the four probabilities and the probability that none occur is the product of the four complements. "At least one" is 1 minus the chance that none occur, and "exactly k" sums over every way of choosing which k events happen.

The calculator applies these rules to your four probabilities and lists the result for every count from zero to four. When all four events have the same probability the problem reduces to a binomial distribution, and the page shows that special case.

Below you will find the formulas, a variables table, a worked example and answers to common questions such as what independence means and how this differs from the three-event version.

How to Use the Probability of 4 Events Calculator

  1. Enter P(A), P(B), P(C) and P(D) as decimals, percentages or fractions.
  2. Read “all”, “none” and “at least one” first.
  3. Use the table for the probability of exactly 0, 1, 2, 3 or 4 events, and the cumulative column for “at least k”.
  4. Check the chart to see which count of events is most likely.

Probability of 4 Events Formula

All four (independent)

P(A∩B∩C∩D)=∏ipiP(A\cap B\cap C\cap D)=\prod_{i}p_i

At least one

P(≥1)=1−∏i(1−pi)P(\ge1)=1-\prod_{i}(1-p_i)

Exactly k occur

P(K=k)=∑∣S∣=k∏i∈Spi∏j∉S(1−pj)P(K=k)=\sum_{|S|=k}\prod_{i\in S}p_i\prod_{j\notin S}(1-p_j)

Equal probabilities (binomial special case)

P(K=k)=(4k)pk(1−p)4−kP(K=k)=\binom{4}{k}p^k(1-p)^{4-k}

Probability of 4 Events Variables Explained

SymbolMeaningNotes
P(A)…P(D)Probability of each event0 to 1
P(all)All four occurProduct of the four
P(none)None occurProduct of the complements
P(≥1)At least one occurs1 − P(none)
kNumber of events that occur0 to 4

Probability of 4 Events Worked Example

Using the example values (press “Load example” above to try them):

  1. Assuming independence, P(all) = 0.6 × 0.5 × 0.3 × 0.1 = 0.009.
  2. P(none) = (1 − 0.6) × (1 − 0.5) × (1 − 0.3) × (1 − 0.1) = 0.126.
  3. P(at least one) = 1 − P(none) = 0.874.
  4. P(exactly k) is found by adding the probabilities of every combination with k events happening and the rest failing: k=0: 0.126, k=1: 0.383, k=2: 0.365, k=3: 0.117, k=4: 0.009.

Result: All 4 events occur P(A ∩ B ∩ C ∩ D) = 0.009; None occur = 0.126; At least one occurs P(A ∪ B ∪ …) = 0.874.

Worked example

A project depends on four independent risks occurring with probabilities 0.6, 0.5, 0.3 and 0.1. The chance none occurs is 0.4 × 0.5 × 0.7 × 0.9 = 0.126, so the chance at least one occurs is 0.874. All four occurring has probability 0.6 × 0.5 × 0.3 × 0.1 = 0.009. The most likely number of risks to occur is shown by the tallest bar in the chart.

When all four probabilities are equal

If each event has the same probability p, the number of events that occur follows a binomial distribution with n = 4. For example, with four fair coin flips (p = 0.5) the probabilities of 0 to 4 heads are 1/16, 4/16, 6/16, 4/16 and 1/16. For more than four events, use the binomial calculator.

Four fair coin flips
HeadsCombinationsProbability
011/16 = 6.25%
144/16 = 25%
266/16 = 37.5%
344/16 = 25%
411/16 = 6.25%

What if the events are dependent?

If one event changes the probability of another, as when drawing without replacement, independence fails and multiplying marginal probabilities gives a wrong answer. You then need conditional probabilities or a joint probability model. When events are mutually exclusive, the chance that one of them happens is the sum of their probabilities.

Where Probability of 4 Events Is Used

Multi-component reliability

Chance that all four parts work, or that at least one fails.

Sequences of independent outcomes

Combining four separate chances.

Coursework

Checking answers on all, none and exactly-k probabilities.

Risk of at least one event

Estimating the chance that something occurs at least once across four independent chances.

Common Probability of 4 Events Mistakes to Avoid

  • Probabilities of independent events multiply; those of mutually exclusive events add.
  • Check that none of your four events is a subset or restatement of another.
  • The complement is the fastest route to “at least one”.

Probability of 4 Events Terms and Definitions

Poisson-binomial distribution
The distribution of the number of successes among independent trials with different success probabilities.

Probability of 4 Events FAQs

How do I calculate the probability of 4 events?

For independent events multiply the four probabilities to get the chance all occur. For at least one, compute 1 minus the product of (1 − p) for each event.

How do I find the probability of exactly two of four events?

Add the probability of every pair occurring while the other two fail. This calculator does the sum for you.

Does the order of events matter?

No. The results do not depend on which event is called A, B, C or D.

What if all four have the same probability?

Then the number of occurrences follows a binomial distribution with n = 4.

Can the probabilities add up to more than 1?

Yes, for independent events they are separate probabilities and need not sum to 1. Only mutually exclusive, exhaustive events must sum to 1.

What does the chart show?

The probability that exactly 0, 1, 2, 3 or all 4 of the events occur.

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Last updated 2026-11-09. See our disclaimer.